How would I found the probability if a person brought 1 share of Google stock within the last year if the stock closed at less than the mean of 59.30 and it has a standard deviation of 32.88589462.

How would I found the probability if a person brought 1 share of Google

stock within the last year if the stock closed at less than the mean of 59.30 and it has a standard deviation of 32.88589462. The mean can’t be calculated in the calculation. Would the probability be the same for any normal distribution?

 
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If a person bought 1 share of Google stock within the last year, the probability the stock closed at more or less than $1150.

If a person bought 1 share of Google stock within the last year, the probability the stock closed at more or less than $1150. I would have to find the z-score for the $1150 by calculating $1150- 59.30/32.89 =33.16 or 33.2 According to the z table it is .9995. Then I would 1-.9995= .0005 or 5%.

 
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If a person bought 1 share of Google stock within the last year,

If a person bought 1 share of Google stock

within the last year, what is the probability that the stock on that day closed at less than $950 per share. Would this be considered unusual? Use the definition of unusual from the course textbook that is measured as a number of standard deviations. In order find the z-score I’d subtract the mean of 59.3 from $950 and divide the standard deviation. z=(x−μ)/σ, z=(950-59.30)/32.89 = 27.08.

 
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If a person bought 1 share of Google stock within the last year

If a person bought 1 share of Google

stock within the last year, what is the probability that the stock on that day closed at less than $950 per share. Would this be considered unusual? Use the definition of unusual from the course textbook that is measured as a number of standard deviations. The mean is 59.30 and the standard deviation is 32.88589462. How could this be calculated.

 
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Ben is a Morgan horse at a Colorado dude ranch.

Gentle

Ben is a Morgan horse at a Colorado dude ranch. Over the past 8 weeks, a veterinarian took the following glucose readings from this horse (in mg/100 ml).
94
87
81
103
98
111
85
88

The sample mean is x ≈ 93.4. Let x be a random variable representing glucose readings taken from Gentle Ben. We may assume that x has a normal distribution, and we know from past experience that σ = 12.5. The mean glucose level for horses should be μ = 85 mg/100 ml.† Do these data indicate that Gentle Ben has an overall average glucose level higher than 85? Use α = 0.05.
(a)  What is the level of significance?
State the null and alternate hypotheses. Will you use a left-tailed, right-tailed, or two-tailed test?
(b)   What sampling distribution will you use? Explain the rationale for your choice of sampling distribution.
Compute the z value of the sample test statistic. (Round your answer to two decimal places.)

(c)    Find (or estimate) the P-value. (Round your answer to four decimal places.)

Sketch the sampling distribution and show the area corresponding to the P-value.

(a)   Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis? Are the data statistically significant at level α?
(b)  State your conclusion in the context of the application.

 
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Do the given data indicate that the population mean RBC count for this patient is lower than 4.68? Use α = 0.05.

Do the given data indicate that the population mean RBC count for this patient is lower than 4.68? Use α = 0.05.

(a) What is the level of significance? 0.05

What is the null and alternate hypotheses?.

(b) What sampling distribution can be used? Explain

What is the value of the sample test statistic? (Round your answer to three decimal places.)

(c) Estimate the P-value.

(d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis? Are the data statistically significant at level α?

e) Interpret your conclusion in the context of the application.

 
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Let x be a random variable that represents red blood cell count (RBC) in millions of cells per cubic millimeter of whole blood.

Let x be a random variable that represents

red blood cell count (RBC) in millions of cells per cubic millimeter of whole blood. Then x has a distribution that is approximately normal. For the population of healthy female adults, suppose the mean of the x distribution is about 4.68. Suppose that a female patient has taken six laboratory blood tests over the past several months and that the RBC count data sent to the patient’s doctor are as follows.
4.9 4.2 4.5 4.1 4.4 4.3
(i) Use a calculator with sample mean and standard deviation keys to find x and s. (Round your answers to two decimal places.)
What is x=
and what is s=

 
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The dial of a “combination lock” has the numbers 0 through 34.

The dial of a “combination lock” has

the numbers 0 through 34. The “combination” to open the lock is actually an ordered sequence of 3 numbers. Each ordered sequence, from your textbook, is called an ‘outcome’. How many outcomes are possible for this lock?

 
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Construct a difference table to predict the next term of the sequence.

Construct a difference table to predict the next term of the sequence.

−1, 3, 19, 54, 115, 209, 343, . . .

 
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Find the difference. 7403eight − 546eight

Find the difference. 7403eight − 546eight

 
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